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Physics · SYSTEMS OF PARTICLES AND ROTATIONAL MOTION

हिन्दी

A light rigid rod of length \( l \) has two point masses, each of mass \( \frac{M}{2} \), attached at its two ends. The moment of inertia of this system about an axis passing through its centre and perpendicular to the rod is:

  1. \( \frac{1}{2} M l^2 \)
  2. \( \frac{1}{4} M l^2 \)
  3. \( M l^2 \)
  4. \( \frac{1}{8} M l^2 \)

Correct answer · Option 2

\( \frac{1}{4} M l^2 \)

Explanation

Distance of each mass from the central axis is \( l/2 \). Thus, \( I = 2 \times [(\frac{M}{2})(\frac{l}{2})^2] = \frac{M l^2}{4} \).
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