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Physics · GRAVITATION
हिन्दीThe work done in lifting a particle of mass \( m \) from a distance \( r_1 \) to \( r_2 \) (\( r_2 > r_1 \)) from the centre of the Earth of mass \( M_E \) along a vertical path is:
Correct answer · Option 1
\( -G M_E m ( \frac{1}{r_2} - \frac{1}{r_1} ) \)
Explanation
Work done against gravity is \( W_{12} = \int_{r_1}^{r_2} \frac{G M_E m}{r^2} dr = -G M_E m ( \frac{1}{r_2} - \frac{1}{r_1} ) \).
