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Physics · PYQ NEET UG 2018
हिन्दीA pendulum is hung from the roof of a sufficiently high building and is moving freely to and fro like a simple harmonic oscillator. The acceleration of the bob of the pendulum is \( 20 \text{ m/s}^2 \) at a distance of \( 5 \text{ m} \) from the mean position. The time period of oscillation is
Correct answer · Option 2
\( \pi \text{ s} \)
Explanation
Magnitude of acceleration is \( a = \omega^2 x \). Given \( a = 20 \) and \( x = 5 \), so \( \omega^2 = \frac{20}{5} = 4 \Rightarrow \omega = 2 \text{ rad/s} \). Time period \( T = \frac{2\pi}{\omega} = \frac{2\pi}{2} = \pi \text{ s} \).
