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Physics · PYQ NEET UG 2024
हिन्दीA wire of length \( l \) and resistance \( 100\ \Omega \) is divided into 10 equal parts. The first 5 parts are connected in series while the next 5 parts are connected in parallel. The two combinations are again connected in series. The resistance of this final combination is:
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Correct answer · Option D
\( 52\ \Omega \)
Explanation
Each part has resistance \( r = 10\ \Omega \). First 5 in series: \( R_1 = 5 \times 10 = 50\ \Omega \). Next 5 in parallel: \( R_2 = 10 / 5 = 2\ \Omega \). Total resistance \( R = 50 + 2 = 52\ \Omega \).
