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Physics · MOTION IN A STRAIGHT LINE
हिन्दीAn object starts moving from position \( x_0 = 10\text{ m} \) at time \( t = 0 \) with initial velocity \( v_0 = -4\text{ m s}^{-1} \) and uniform acceleration \( a = 2\text{ m s}^{-2} \). What is the position of the object when its velocity temporarily becomes zero?
Correct answer · Option 2
\( 6\text{ m} \)
Explanation
Using \( v^2 = v_0^2 + 2a(x - x_0) \), set \( v = 0 \): \( 0 = (-4)^2 + 2(2)(x - 10) \implies 0 = 16 + 4(x - 10) \implies x - 10 = -4 \implies x = 6\text{ m} \).
