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Physics · LAWS OF MOTION
हिन्दीMatch List-I (Physical Quantity) with List-II (Definition / Formula): List-I List-II A Momentum (\( \mathbf{p} \)) I Net external force (\( \mathbf{F} \)) B Time derivative of momentum (\( d\mathbf{p}/dt \)) II Zero acceleration C Impulse III Product of mass and velocity (\( m\mathbf{v} \)) D Net force zero (\( \mathbf{F} = 0 \)) IV Change in momentum (\( \Delta \mathbf{p} \)) Choose the correct answer from the options given below:
Match List-I (Physical Quantity) with List-II (Definition / Formula):
| List-I | List-II | ||
|---|---|---|---|
| A | Momentum (\( \mathbf{p} \)) | I | Net external force (\( \mathbf{F} \)) |
| B | Time derivative of momentum (\( d\mathbf{p}/dt \)) | II | Zero acceleration |
| C | Impulse | III | Product of mass and velocity (\( m\mathbf{v} \)) |
| D | Net force zero (\( \mathbf{F} = 0 \)) | IV | Change in momentum (\( \Delta \mathbf{p} \)) |
Choose the correct answer from the options given below:
Correct answer · Option 3
A-(III), B-(I), C-(IV), D-(II)
Explanation
Momentum \( \mathbf{p} = m\mathbf{v} \) (III); \( d\mathbf{p}/dt = \mathbf{F} \) (I); Impulse \( = \Delta \mathbf{p} \) (IV); Net force zero implies acceleration is zero (II).
