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Chemistry · EQUILIBRIUM
हिन्दीFor the equilibrium \( 2\text{NOCl}(\text{g}) \rightleftharpoons 2\text{NO}(\text{g}) + \text{Cl}_2(\text{g}) \), \( K_c = 3.75 \times 10^{-6} \) at \( 1069\text{ K} \). Using \( R = 0.0831\text{ bar L mol}^{-1}\text{K}^{-1} \), what is the numerical ratio of \( K_p \) to \( K_c \)?
Correct answer · Option 4
\( 88.83 \)
Explanation
\( \Delta n = (2+1) - 2 = 1 \). Therefore, \( \frac{K_p}{K_c} = (RT)^1 = 0.0831 \times 1069 \approx 88.83 \).
