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Chemistry · EQUILIBRIUM
हिन्दीAt 298 K, the density of pure water is \( 1000\text{ g/L} \) and its ionic product \( K_w \) is \( 1.0 \times 10^{-14}\text{ mol}^2\text{L}^{-2} \). The ratio of dissociated water molecules to undissociated water molecules is approximately:
Correct answer · Option 2
\( 1.8 \times 10^{-9} \)
Explanation
Molarity of pure water = \( 1000/18 = 55.55\text{ M} \). Dissociated water concentration = \( 10^{-7}\text{ M} \). Ratio = \( 10^{-7}/55.55 \approx 1.8 \times 10^{-9} \).
