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Physics · Electrostatic Potential
हिन्दीIf the electric potential at any point in space is given by \( V = 3x^2 + 5 \), the magnitude of the electric field at point \( (1, 0, 0) \) is:
Correct answer · Option 1
\( 6 \, \text{V/m} \)
Explanation
Electric field \( E_x = -\frac{dV}{dx} = -6x \). At \( x = 1 \), magnitude \( |E| = |-6(1)| = 6 \, \text{V/m} \).
