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Physics · PYQ NEET UG 2026
हिन्दीA solid sphere $A$ of radius $R$ and mass $M$ is attached at a point to a smaller solid sphere $B$ of radius $r < R$ and mass $m < M$. Assume that the line joining their centres lies along the horizontal. The moment of inertia of the system calculated about a vertical axis passing through the centre of $A$ is $I_A$ and that calculated about a vertical axis passing through the centre of $B$ is $I_B$. The difference $I_A - I_B$ is :
Correct answer · Option 2
$(m - M)(R + r)^2$
Explanation
Using the parallel axis theorem, shift the moments of inertia to the common reference point and compute the difference $I_A - I_B$, yielding $(m - M)(R + r)^2$.
