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Physics · Electrostatic Potential

हिन्दी

The work done in moving a test charge over an equipotential surface is:

  1. Positive
  2. Negative
  3. Infinite
  4. Zero

Correct answer · Option 4

Zero

Explanation

Since potential is constant on an equipotential surface, \( \Delta V = 0 \), hence work done \( W = q \Delta V = 0 \).

Related questions

A capacitor of capacitance \( C_1 = 4\, \mu\text{F} \) is charged to \( 50\text{ V} \) and another capacitor \( C_2 = 6\, \mu\text{F} \) is charged to \( 100\text{ V} \). If they are connected together in parallel with plates of like polarity connected together, the final common potential difference across the combination is:→Inside a uniformly polarised dielectric slab, the net charge in any macroscopic volume element \( \Delta v \) is zero because:→A conductor and a dielectric slab are placed separately in a uniform external electric field \( \mathbf{E}_0 \). If \( \mathbf{E}_{\text{in}} \) represents the induced electric field inside each material, the net electric field inside them satisfies:→Given below are two statements: Statement I: The formula for electrostatic energy density \( u = \frac{1}{2} \varepsilon_0 E^2 \) is valid only for the uniform electric field between the plates of a parallel plate capacitor. Statement II: The permittivity of a dielectric medium is always smaller than the permittivity of free space. In the light of the above statements, choose the most appropriate answer from the options given below:→
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