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Chemistry · Some Basic Concepts of Chemistry

हिन्दी

A compound containing carbon, hydrogen, and chlorine has an empirical formula of \( \text{CH}_2\text{Cl} \). If its vapour density relative to hydrogen is \( 49.48 \), its molecular formula is:

  1. \( \text{C}_3\text{H}_6\text{Cl}_3 \)
  2. \( \text{C}_2\text{H}_4\text{Cl}_2 \)
  3. \( \text{CH}_2\text{Cl} \)
  4. \( \text{C}_4\text{H}_8\text{Cl}_2 \)

Correct answer · Option 2

\( \text{C}_2\text{H}_4\text{Cl}_2 \)

Explanation

Molar mass \( = 2 \times \text{vapour density} = 2 \times 49.48 = 98.96\text{ g/mol} \). Empirical formula mass of \( \text{CH}_2\text{Cl} = 12.01 + 2(1.008) + 35.45 = 49.48\text{ g/mol} \). Ratio \( n = 98.96 / 49.48 = 2 \). Molecular formula \( = (\text{CH}_2\text{Cl})_2 = \text{C}_2\text{H}_4\text{Cl}_2 \).
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