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Physics · MOTION IN A STRAIGHT LINE
हिन्दीA ball is thrown vertically upwards with a velocity of \( 20\text{ m s}^{-1} \) from the top of a building. Taking \( g = 10\text{ m s}^{-2} \), what is the maximum height reached above the point of launch?
Correct answer · Option 3
\( 20\text{ m} \)
Explanation
Using \( v^2 = v_0^2 + 2a(y - y_0) \) where \( v = 0 \), \( v_0 = 20 \), \( a = -10 \), we get \( 0 = 20^2 + 2(-10)y \Rightarrow y = 20\text{ m} \).
