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Physics · SYSTEMS OF PARTICLES AND ROTATIONAL MOTION
हिन्दीThe angular speed of a flywheel increases uniformly from \( 1200\text{ rpm} \) to \( 3120\text{ rpm} \) in \( 16\text{ seconds} \). The angular acceleration of the flywheel is:
Correct answer · Option 2
\( 4\pi\text{ rad/s}^2 \)
Explanation
\( \omega_0 = \frac{2\pi \times 1200}{60} = 40\pi\text{ rad/s} \), \( \omega = \frac{2\pi \times 3120}{60} = 104\pi\text{ rad/s} \). Then \( \alpha = \frac{\omega - \omega_0}{t} = \frac{104\pi - 40\pi}{16} = 4\pi\text{ rad/s}^2 \).
