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Physics · PYQ NEET UG 2018
हिन्दीAn electron falls from rest through a vertical distance '\( h \)' in a uniform and vertically upward directed electric field '\( E \)'. The direction of the electric field is now reversed, keeping its magnitude the same. A proton is allowed to fall from rest in it through the same vertical distance '\( h \)'. The time of fall of the electron, in comparison to the time of fall of the proton is
Correct answer · Option 1
smaller.
Explanation
Time \( t = \sqrt{\frac{2h}{a}} = \sqrt{\frac{2hm}{eE}} \). Since \( m_p > m_e \), the time of fall for the electron is smaller than that for the proton.
