OnlineCBT
Chemistry · CHEMICAL BONDING AND MOLECULAR STRUCTURE
हिन्दीIn \( \text{NH}_3 \) and \( \text{NF}_3 \), both have pyramidal geometry with nitrogen having a lone pair. Given that \( \mu_{\text{NH}_3} = 4.90 \times 10^{-30}\text{ C m} \) and \( \mu_{\text{NF}_3} = 0.80 \times 10^{-30}\text{ C m} \), calculate the numerical ratio \( \mu_{\text{NH}_3} / \mu_{\text{NF}_3} \) expressed to two decimal places.
Correct answer · Option 3
\( 6.13 \)
Explanation
\( \frac{\mu_{\text{NH}_3}}{\mu_{\text{NF}_3}} = \frac{4.90 \times 10^{-30}}{0.80 \times 10^{-30}} = \frac{4.90}{0.80} = 6.125 \approx 6.13 \).
