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Chemistry · EQUILIBRIUM
हिन्दीMatch List-I with List-II: List-I (Salt Type / Solution) List-II (pH Expression at 298 K) A Salt of Weak Acid & Strong Base I \( pH = 7 \) (No hydrolysis) B Salt of Strong Acid & Weak Base II \( pH = 7 + \frac{1}{2}(pK_a - pK_b) \) C Salt of Weak Acid & Weak Base III \( pH = 7 + \frac{1}{2}pK_a + \frac{1}{2}\log C \) D Salt of Strong Acid & Strong Base IV \( pH = 7 - \frac{1}{2}pK_b - \frac{1}{2}\log C \) Choose the correct answer from the options given below:
Match List-I with List-II:
| List-I (Salt Type / Solution) | List-II (pH Expression at 298 K) | ||
|---|---|---|---|
| A | Salt of Weak Acid & Strong Base | I | \( pH = 7 \) (No hydrolysis) |
| B | Salt of Strong Acid & Weak Base | II | \( pH = 7 + \frac{1}{2}(pK_a - pK_b) \) |
| C | Salt of Weak Acid & Weak Base | III | \( pH = 7 + \frac{1}{2}pK_a + \frac{1}{2}\log C \) |
| D | Salt of Strong Acid & Strong Base | IV | \( pH = 7 - \frac{1}{2}pK_b - \frac{1}{2}\log C \) |
Choose the correct answer from the options given below:
Correct answer · Option 2
A-(III), B-(IV), C-(II), D-(I)
Explanation
Weak acid + strong base gives alkaline solution: \( pH = 7 + \frac{1}{2}pK_a + \frac{1}{2}\log C \); Strong acid + weak base gives acidic solution: \( pH = 7 - \frac{1}{2}pK_b - \frac{1}{2}\log C \); Weak acid + weak base: \( pH = 7 + \frac{1}{2}(pK_a - pK_b) \); Strong acid + strong base: \( pH = 7 \).
