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Physics · Electrostatic Potential

हिन्दी

Three charges \( +q, +q \) and \( -q \) are placed at the vertices of an equilateral triangle of side \( d \). The total potential energy of the system is:

  1. \( \frac{1}{4\pi\varepsilon_0} \frac{q^2}{d} \)
  2. \( -\frac{1}{4\pi\varepsilon_0} \frac{q^2}{d} \)
  3. \( \frac{1}{4\pi\varepsilon_0} \frac{3q^2}{d} \)
  4. \( -\frac{1}{4\pi\varepsilon_0} \frac{3q^2}{d} \)

Correct answer · Option 2

\( -\frac{1}{4\pi\varepsilon_0} \frac{q^2}{d} \)

Explanation

Summing pair-wise potential energies: \( U = \frac{1}{4\pi\varepsilon_0} (\frac{q^2}{d} - \frac{q^2}{d} - \frac{q^2}{d}) = -\frac{1}{4\pi\varepsilon_0} \frac{q^2}{d} \).
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