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Chemistry · THERMODYNAMICS

हिन्दी

Three moles of an ideal gas expand isothermally and reversibly from an initial pressure of \( 10.0\text{ atm} \) to a final pressure of \( 1.0\text{ atm} \) at \( 300\text{ K} \). The work done by the gas is: (Given: \( R = 8.314\text{ J}\cdot\text{K}^{-1}\cdot\text{mol}^{-1} \), \( \ln 10 = 2.303 \))

  1. A
    \( -5744\text{ J} \)
  2. B
    \( +17232\text{ J} \)
  3. C
    \( +5744\text{ J} \)
  4. D
    \( -17232\text{ J} \)

Correct answer · Option D

\( -17232\text{ J} \)

Explanation

\( w_{\text{rev}} = -2.303 nRT \log(p_i/p_f) = -2.303 \times 3 \times 8.314 \times 300 \times \log(10/1) = -17232\text{ J} \).
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