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Physics · GRAVITATION

हिन्दी

At what depth \( d \) below the Earth's surface does the acceleration due to gravity reduce to half of its value at the Earth's surface \( g \)? (Take radius of Earth as \( R_E \))

  1. \( \frac{R_E}{4} \)
  2. \( \frac{R_E}{2} \)
  3. \( \frac{3R_E}{4} \)
  4. \( \frac{R_E}{\sqrt{2}} \)

Correct answer · Option 2

\( \frac{R_E}{2} \)

Explanation

Using g(d) = g (1 - d / R_E), setting g(d) = g / 2 gives 1 - d / R_E = 1/2, so d = R_E / 2.
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