OnlineCBT
Chemistry · Structure of atom
हिन्दीCalculate the energy of an electron in the second stationary state (\( n = 2 \)) of a hydrogen atom (\( R_H = 2.18 \times 10^{-18} \text{ J} \)).
Correct answer · Option 1
\( -0.545 \times 10^{-18} \text{ J} \)
Explanation
Using \( E_n = -R_H (\frac{1}{n^2}) \), for \( n = 2 \), \( E_2 = -2.18 \times 10^{-18} (\frac{1}{2^2}) = -0.545 \times 10^{-18} \text{ J} \).
