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Physics · SYSTEMS OF PARTICLES AND ROTATIONAL MOTION
हिन्दीIn the mechanical setup shown below, a non-uniform bar of weight \( W \) and length \( 2 \text{ m} \) hangs horizontally in static equilibrium supported by two light strings. The strings make angles \( 36.9^\circ \) and \( 53.1^\circ \) with the vertical walls. The ratio of the tensions in the left string to the right string (\( T_1 / T_2 \)) is:
Correct answer · Option 2
\( 4/3 \)
Explanation
For translational equilibrium in the horizontal direction: \( T_1 \sin 36.9^\circ = T_2 \sin 53.1^\circ \). Since \( \sin 36.9^\circ = 0.6 \) and \( \sin 53.1^\circ = 0.8 \), \( \frac{T_1}{T_2} = \frac{\sin 53.1^\circ}{\sin 36.9^\circ} = \frac{0.8}{0.6} = \frac{4}{3} \).
