OnlineCBT
Physics · PYQ NEET UG 2021
हिन्दीA screw gauge gives the following readings when used to measure the diameter of a wire Main scale reading: \( 0\text{ mm} \) Circular scale reading: \( 52\text{ divisions} \) Given that \( 1\text{ mm} \) on main scale corresponds to \( 100\text{ divisions} \) on the circular scale. The diameter of the wire from the above data is:
Correct answer · Option 3
0.052 cm
Explanation
Least count (LC) of the screw gauge is given by:
\( \text{LC} = \frac{1\text{ mm}}{100} = 0.01\text{ mm} = 0.001\text{ cm} \)
The diameter of the wire is calculated as:
\( d = \text{Main Scale Reading (MSR)} + (\text{Circular Scale Reading (CSR)} \times \text{LC}) \)
\( d = 0 + (52 \times 0.001\text{ cm}) = 0.052\text{ cm} \)
\( \text{LC} = \frac{1\text{ mm}}{100} = 0.01\text{ mm} = 0.001\text{ cm} \)
The diameter of the wire is calculated as:
\( d = \text{Main Scale Reading (MSR)} + (\text{Circular Scale Reading (CSR)} \times \text{LC}) \)
\( d = 0 + (52 \times 0.001\text{ cm}) = 0.052\text{ cm} \)
