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Physics · PYQ NEET UG 2021
हिन्दीA spring is stretched by \( 5\text{ cm} \) by a force \( 10\text{ N} \). The time period of the oscillations when a mass of \( 2\text{ kg} \) is suspended by it is
Correct answer · Option 3
0.628 s
Explanation
Spring constant \( k = \frac{F}{x} = \frac{10\text{ N}}{0.05\text{ m}} = 200\text{ N/m} \). Time period \( T = 2\pi \sqrt{\frac{m}{k}} = 2\pi \sqrt{\frac{2}{200}} = \frac{2\pi}{10} = \frac{2 \times 3.1416}{10} = 0.628\text{ s} \).
