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Physics · MOTION IN A PLANE
हिन्दीA cricket ball is thrown at a speed of \( 28\text{ m/s} \) in a direction \( 30^\circ \) above the horizontal. Taking \( g = 9.8\text{ m/s}^2 \), the maximum height \( h_m \), total time of flight \( T_f \), and horizontal distance from thrower to landing point \( R \) are respectively:
Correct answer · Option 4
\( h_m = 10.0\text{ m} \), \( T_f = 2.9\text{ s} \), \( R = 69\text{ m} \)
Explanation
\( h_m = \frac{(28 \sin 30^\circ)^2}{2(9.8)} = \frac{14^2}{19.6} = 10.0\text{ m} \). \( T_f = \frac{2(28)\sin 30^\circ}{9.8} = 2.9\text{ s} \). \( R = \frac{28^2 \sin 60^\circ}{9.8} \approx 69\text{ m} \).
