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Physics · PYQ NEET UG 2019(2)

हिन्दी

Assuming that the gravitational potential energy of an object at infinity is zero, the change in potential energy (final - initial) of an object of mass \( m \), when taken to a height \( h \) from the surface of earth (of radius \( R \)), is given by,

  1. \( \frac{GMm}{R+h} \)
  2. \( -\frac{GMm}{R+h} \)
  3. \( \frac{GMmh}{R(R+h)} \)
  4. \( mgh \)

Correct answer · Option 3

\( \frac{GMmh}{R(R+h)} \)

Explanation

Initial potential energy at surface \( U_i = -\frac{GMm}{R} \). Final potential energy at height \( h \), \( U_f = -\frac{GMm}{R+h} \). Change \( \Delta U = U_f - U_i = -\frac{GMm}{R+h} - (-\frac{GMm}{R}) = \frac{GMmh}{R(R+h)} \).
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