The output (\( Y \)) of the given logic gate is similar to the output of an/a :

The top gate acts as NOT A (\( \bar{A} \)) and bottom gate as NOT B (\( \bar{B} \)). These inputs fed into a NOR gate give \( Y = \overline{\bar{A} + \bar{B}} = A \cdot B \), which is an AND gate.