Chemistry · THERMODYNAMICS
हिन्दीGiven the standard molar enthalpies of formation at 298 K: \( \Delta_f H^\ominus[\text{CH}_4(g)] = -74.81\text{ kJ mol}^{-1} \), \( \Delta_f H^\ominus[\text{CO}_2(g)] = -393.51\text{ kJ mol}^{-1} \), and \( \Delta_f H^\ominus[\text{H}_2\text{O}(l)] = -285.83\text{ kJ mol}^{-1} \). The standard enthalpy of combustion of methane, \( \text{CH}_4(g) + 2\text{O}_2(g) \rightarrow \text{CO}_2(g) + 2\text{H}_2\text{O}(l) \), is:
Correct answer · Option 2
-890.36 kJ mol⁻¹
Explanation
\( \Delta_r H^\ominus = [-393.51 + 2(-285.83)] - [-74.81] = -965.17 + 74.81 = -890.36\text{ kJ mol}^{-1} \).