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Physics · PYQ NEET UG 2016(2)
हिन्दीThe temperature inside a refrigerator is \( t_2\ ^\circ\text{C} \) and the room temperature is \( t_1\ ^\circ\text{C} \). The amount of heat delivered to the room for each joule of electrical energy consumed ideally will be
Correct answer · Option 3
\( \frac{t_1 + 273}{t_1 - t_2} \)
Explanation
COP \( = \frac{Q_2}{W} = \frac{T_2}{T_1 - T_2} \). Heat delivered to room \( Q_1 = Q_2 + W = \frac{T_2}{T_1 - T_2} + 1 = \frac{T_1}{T_1 - T_2} = \frac{t_1 + 273}{(t_1 + 273) - (t_2 + 273)} = \frac{t_1 + 273}{t_1 - t_2} \).
