Chemistry · PYQ NEET UG 2026
हिन्दीIn acidic medium, $10\text{ mL}$ of $0.25\text{ M}$ oxalic acid is titrated with $\text{KMnO}_4$ solution. If the volume of $\text{KMnO}_4$ solution required to reach end point is $10\text{ mL}$, the strength of the $\text{KMnO}_4$ solution is
Correct answer · Option 1
$0.10\text{ M}$
Explanation
Milli-equivalents of oxalic acid = Milli-equivalents of $\text{KMnO}_4$. $10 \times 0.25 \times 2 = 10 \times M \times 5 \implies M = \frac{0.5}{5} = 0.10\text{ M}$.