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Physics · MOTION IN A STRAIGHT LINE
हिन्दीA man walks on a straight road from his home to a market \( 2.5\text{ km} \) away at a speed of \( 5\text{ km/h} \). Finding the market closed, he instantly turns and walks back home at a speed of \( 7.5\text{ km/h} \). Match the time intervals in List-I with the corresponding values of average speed/velocity in List-II: List-I List-II A Average speed in interval \( 0\text{ to }30\text{ min} \) I \( 0\text{ km/h} \) B Average speed in interval \( 0\text{ to }50\text{ min} \) II \( 5.625\text{ km/h} \) C Magnitude of average velocity in interval \( 0\text{ to }50\text{ min} \) III \( 5\text{ km/h} \) D Average speed in interval \( 0\text{ to }40\text{ min} \) IV \( 6\text{ km/h} \) Choose the correct answer from the options given below:
A man walks on a straight road from his home to a market \( 2.5\text{ km} \) away at a speed of \( 5\text{ km/h} \). Finding the market closed, he instantly turns and walks back home at a speed of \( 7.5\text{ km/h} \). Match the time intervals in List-I with the corresponding values of average speed/velocity in List-II:
| List-I | List-II | ||
|---|---|---|---|
| A | Average speed in interval \( 0\text{ to }30\text{ min} \) | I | \( 0\text{ km/h} \) |
| B | Average speed in interval \( 0\text{ to }50\text{ min} \) | II | \( 5.625\text{ km/h} \) |
| C | Magnitude of average velocity in interval \( 0\text{ to }50\text{ min} \) | III | \( 5\text{ km/h} \) |
| D | Average speed in interval \( 0\text{ to }40\text{ min} \) | IV | \( 6\text{ km/h} \) |
Choose the correct answer from the options given below:
Correct answer · Option 1
A-(III), B-(IV), C-(I), D-(II)
Explanation
In 0-30 min: distance = 2.5 km, average speed = 5 km/h (A-III). In 0-50 min: total distance = 5 km, total time = 5/6 h, average speed = 6 km/h (B-IV). In 0-50 min: total displacement = 0, average velocity = 0 (C-I). In 0-40 min: dist = 2.5 + 1.25 = 3.75 km, time = 2/3 h, average speed = 5.625 km/h (D-II).
