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Chemistry · EQUILIBRIUM
हिन्दीFor a \( 0.05\text{ M} \) ammonia solution having \( K_b = 1.77 \times 10^{-5} \), the degree of ionization (\( \alpha \)) is approximately:
Correct answer · Option 3
\( 0.018 \)
Explanation
Using Ostwald's dilution law for a weak electrolyte, \( \alpha = \sqrt{\frac{K_b}{c}} = \sqrt{\frac{1.77 \times 10^{-5}}{0.05}} = \sqrt{3.54 \times 10^{-4}} \approx 0.018 \).
