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Chemistry · PYQ NEET UG 2019(2)
हिन्दीA first order reaction has a rate constant of \( 2.303 \times 10^{-3} \text{ s}^{-1} \). The time required for 40 g of this reactant to reduce to 10 g will be [Given that \( \log_{10} 2 = 0.3010 \)]
Correct answer · Option 1
602 s
Explanation
For a first order reaction, \( t = \frac{2.303}{k} \log \frac{[A]_0}{[A]} = \frac{2.303}{2.303 \times 10^{-3}} \log \frac{40}{10} = 10^3 \times \log 4 = 1000 \times 0.602 = 602 \text{ s} \).
