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Physics · PYQ NEET UG 2017
हिन्दीA capacitor is charged by a battery. The battery is removed and another identical uncharged capacitor is connected in parallel. The total electrostatic energy of resulting system
Correct answer · Option 2
decreases by a factor of 2
Explanation
Initial energy \( U_i = \frac{1}{2}CV^2 \). When connected in parallel to an identical uncharged capacitor, charge divides equally, so new potential is \( \frac{V}{2} \) and equivalent capacitance is \( 2C \). Final energy \( U_f = \frac{1}{2}(2C)(\frac{V}{2})^2 = \frac{1}{4}CV^2 = \frac{U_i}{2} \).
