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Physics · PYQ NEET UG 2019(2)
हिन्दीA proton and an \( \alpha \)-particle are accelerated from rest to the same energy. The de Broglie wavelengths \( \lambda_p \) and \( \lambda_\alpha \) are in the ratio,
Correct answer · Option 2
\( 2 : 1 \)
Explanation
De Broglie wavelength \( \lambda = \frac{h}{\sqrt{2mE}} \). Since energy \( E \) and \( h \) are same, \( \lambda \propto \frac{1}{\sqrt{m}} \). Thus \( \frac{\lambda_p}{\lambda_\alpha} = \sqrt{\frac{m_\alpha}{m_p}} = \sqrt{\frac{4}{1}} = 2:1 \).
