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Physics · Electrostatic Potential

हिन्दी

A hollow conducting spherical shell of radius \( R \) has a total charge \( q \) distributed uniformly on its surface. The electric potential at a distance \( r \) from the centre, where \( r < R \), is:

  1. \( \frac{1}{4\pi\varepsilon_0} \frac{q}{r} \)
  2. \( \frac{1}{4\pi\varepsilon_0} \frac{q}{R} \)
  3. Zero
  4. \( \frac{1}{4\pi\varepsilon_0} \frac{qr}{R^2} \)

Correct answer · Option 2

\( \frac{1}{4\pi\varepsilon_0} \frac{q}{R} \)

Explanation

Inside a hollow conducting spherical shell, the electric field \( E \) is zero everywhere (\( E = 0 \)) because charges reside only on the outer surface of a conductor in electrostatic equilibrium. Since the electric field is related to electric potential by \( E = -\frac{dV}{dr} \), a zero electric field implies that the electric potential remains constant throughout the interior region and is equal to the potential at the surface. Therefore, for any point where \( r < R \), the electric potential is given by \( V = \frac{1}{4\pi\varepsilon_0} \frac{q}{R} \).
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