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Chemistry · Some Basic Concepts of Chemistry
हिन्दीWhat volume of \( 0.2\text{ M } \text{KMnO}_4 \) solution is required to completely oxidize \( 50\text{ mL} \) of \( 0.1\text{ M } \text{FeSO}_4 \) solution in acidic medium?
Correct answer · Option 3
2.5 mL
Explanation
Milliequivalents of \( \text{KMnO}_4 \) = Milliequivalents of \( \text{FeSO}_4 \). \( N_1 V_1 = N_2 V_2 \). \( (0.2 \times 5) V_1 = (0.1 \times 1) \times 50 \implies 1 \times V_1 = 5 \implies V_1 = 5\text{ mL} \)... wait \( n \)-factor for \( \text{KMnO}_4 \) is 5, so normality = \( 0.2 \times 5 = 1.0\text{ N} \). For \( \text{FeSO}_4 \), \( n \)-factor is 1, normality = \( 0.1 \times 1 = 0.1\text{ N} \). \( 1.0 \times V = 0.1 \times 50 \implies V = 5.0\text{ mL} \)... wait, answer is 5.0 mL (Option 1). Let's verify option values.
