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Chemistry · EQUILIBRIUM
हिन्दीFor the gaseous equilibrium \( 4\text{NH}_3(\text{g}) + 5\text{O}_2(\text{g}) \rightleftharpoons 4\text{NO}(\text{g}) + 6\text{H}_2\text{O}(\text{g}) \), the equilibrium constant expression is \( K_c \). If the stoichiometric coefficients of all reactants and products are halved, the new equilibrium constant \( K_c' \) is related to \( K_c \) as:
Correct answer · Option 2
\( K_c' = \sqrt{K_c} \)
Explanation
When a chemical equation is multiplied throughout by a factor \( n \), the new equilibrium constant becomes \( K_c' = (K_c)^n \). Here \( n = 1/2 \), hence \( K_c' = (K_c)^{1/2} = \sqrt{K_c} \).
