OnlineCBT
Physics · MOTION IN A PLANE
हिन्दीA particle is projected from ground level with speed \( v_0 \) at an angle \( \theta \) above horizontal (\( \tan\theta > 1 \)). The time after projection when the direction of motion of the projectile makes an angle of \( 45^\circ \) with the horizontal is:
Correct answer · Option 1
\( \frac{v_0}{g}(\sin\theta - \cos\theta) \)
Explanation
At angle \( 45^\circ \), \( \tan 45^\circ = 1 = \frac{v_y}{v_x} \implies v_y = v_x \implies v_0 \sin\theta - gt = v_0 \cos\theta \implies t = \frac{v_0}{g}(\sin\theta - \cos\theta) \).
