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Chemistry · EQUILIBRIUM
हिन्दीWhat is the \( [\text{OH}^-] \) concentration in a \( 0.05\text{ M} \) aqueous solution of ammonia (\( K_b = 1.8 \times 10^{-5} \)) at \( 298\text{ K} \)? (Assume \( \alpha \ll 1 \))
Correct answer · Option 4
\( 9.49 \times 10^{-4}\text{ M} \)
Explanation
\( [\text{OH}^-] = \sqrt{K_b \cdot c} = \sqrt{1.8 \times 10^{-5} \times 0.05} = \sqrt{9.0 \times 10^{-7}} = \sqrt{90 \times 10^{-8}} \approx 9.49 \times 10^{-4}\text{ M} \).
