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Physics · SYSTEMS OF PARTICLES AND ROTATIONAL MOTION
हिन्दीA thin uniform circular ring of mass \( M \) and radius \( R \) has a moment of inertia \( I_0 \) about an axis perpendicular to its plane and passing through its centre. If the ring is cut into two equal semicircular halves, the moment of inertia of one semicircular half of mass \( M/2 \) about the same original central axis is:
Correct answer · Option 4
\( \frac{I_0}{2} \)
Explanation
Every mass element of the semicircle remains at a perpendicular distance \( R \) from the axis. Thus \( I = (M/2)R^2 = \frac{1}{2}(MR^2) = \frac{I_0}{2} \).
