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Chemistry · THERMODYNAMICS
हिन्दीIn a process, \( 701\text{ J} \) of heat is absorbed by a system and \( 394\text{ J} \) of work is done by the system. The change in internal energy (\( \Delta U \)) for this process is:
Correct answer · Option 2
\( +307\text{ J} \)
Explanation
By the first law of thermodynamics, \( \Delta U = q + w \). Here, \( q = +701\text{ J} \) and \( w = -394\text{ J} \), so \( \Delta U = 701 - 394 = +307\text{ J} \).
