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Chemistry · PYQ NEET UG 2019(2)
हिन्दीThe volume occupied by 1.8 g of water vapour at 374 °C and 1 bar pressure will be [Use R = 0.083 bar L \text{ K}^{-1} \text{ mol}^{-1}]
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Correct answer · Option A
5.37 L
Explanation
Moles of water \( n = \frac{1.8}{18} = 0.1 \text{ mol} \). Using \( PV = nRT \), \( V = \frac{0.1 \times 0.083 \times 647}{1} = 5.37 \text{ L} \).
