Physics · MOTION IN A PLANE
हिन्दीMatch List-I with List-II: List-I List-II A Time of flight \( T_f \) I \( \frac{2v_o\sin\theta_o}{g} \) B Maximum height \( h_m \) II \( \frac{v_o^2\sin^2\theta_o}{2g} \) C Horizontal range \( R \) III \( \frac{v_o^2\sin 2\theta_o}{g} \) D Angle of projection for maximum range IV \( 45^\circ \) Choose the correct answer from the options given below:
Match List-I with List-II:
| List-I | List-II | ||
|---|---|---|---|
| A | Time of flight \( T_f \) | I | \( \frac{2v_o\sin\theta_o}{g} \) |
| B | Maximum height \( h_m \) | II | \( \frac{v_o^2\sin^2\theta_o}{2g} \) |
| C | Horizontal range \( R \) | III | \( \frac{v_o^2\sin 2\theta_o}{g} \) |
| D | Angle of projection for maximum range | IV | \( 45^\circ \) |
Choose the correct answer from the options given below:
Correct answer · Option 4
A-(I), B-(II), C-(III), D-(IV)
Explanation
The standard projectile formulas are \( T_f = \frac{2v_o\sin\theta_o}{g} \), \( h_m = \frac{v_o^2\sin^2\theta_o}{2g} \), \( R = \frac{v_o^2\sin 2\theta_o}{g} \), and maximum range occurs at \( \theta_o = 45^\circ \).