OnlineCBT
Physics · PYQ NEET UG 2020
हिन्दीA ball is thrown vertically downward with a velocity of \( 20\text{ m/s} \) from the top of a tower. It hits the ground after some time with a velocity of \( 80\text{ m/s} \). The height of the tower is: (\( g = 10\text{ m/s}^2 \))
Correct answer · Option 3
300 m
Explanation
Using kinematic equation \( v^2 - u^2 = 2gH \), we get \( (80)^2 - (20)^2 = 2 \times 10 \times H \), which gives \( 6400 - 400 = 20H \implies H = \frac{6000}{20} = 300\text{ m} \).
