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Physics · WORK, ENERGY AND POWER
हिन्दीA body of mass \( m_1 \) moving with initial velocity \( v_{1i} \) collides head-on completely inelastically with a stationary body of mass \( m_2 \). The fraction of initial kinetic energy lost in the collision is:
Correct answer · Option 1
\( \frac{m_2}{m_1 + m_2} \)
Explanation
Loss in kinetic energy is \( \Delta K = \frac{1}{2}\frac{m_1 m_2}{m_1 + m_2} v_{1i}^2 \). Initial KE is \( K_i = \frac{1}{2}m_1 v_{1i}^2 \). Fraction lost is \( \frac{\Delta K}{K_i} = \frac{m_2}{m_1 + m_2} \).
