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Physics · PYQ NEET UG 2016(1)
हिन्दीA particle of mass \( 10\text{ g} \) moves along a circle of radius \( 6.4\text{ cm} \) with a constant tangential acceleration. What is the magnitude of this acceleration, if the kinetic energy of the particle becomes equal to \( 8 \times 10^{-4}\text{ J} \) by the end of the second revolution after the beginning of the motion?
Correct answer · Option 4
\( 0.1\text{ m/s}^2 \)
Explanation
Distance \( s = 2 \times (2\pi r) = 4\pi \times 6.4 \times 10^{-2}\text{ m} \). Work done \( W = \tau \theta = (F_t r) \theta = m a_t s = \Delta K = 8 \times 10^{-4}\text{ J} \). Solving gives \( a_t = 0.1\text{ m/s}^2 \).
