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Physics · WORK, ENERGY AND POWER
हिन्दीIn a one-dimensional elastic collision, a particle of mass \( m_1 \) moving with velocity \( v_{1i} \) hits a stationary particle of mass \( m_2 \). The fraction of initial kinetic energy transferred to the second particle is:
Correct answer · Option 2
\( \frac{4 m_1 m_2}{(m_1 + m_2)^2} \)
Explanation
Velocity of the second particle is \( v_{2f} = \frac{2m_1}{m_1 + m_2}v_{1i} \). Kinetic energy transferred is \( K_{2f} = \frac{1}{2}m_2 v_{2f}^2 = \frac{1}{2}m_2 \frac{4m_1^2}{(m_1+m_2)^2}v_{1i}^2 \). Fraction of initial energy transferred is \( \frac{K_{2f}}{K_i} = \frac{4 m_1 m_2}{(m_1 + m_2)^2} \).
