Physics · GRAVITATION
हिन्दीIn Cavendish's experiment to measure \( G \), a bar of length \( L \) connects two small lead spheres each of mass \( m \). Two large spheres each of mass \( M \) are placed at a separation \( d \) from the small spheres. If the restoring couple per unit angle of twist of the suspension wire is \( \tau_0 \) and the angle of deflection is \( \theta \), what is the equilibrium relation?
Correct answer · Option 2
\( G\frac{Mm}{d^2} L = \tau_0 \theta \)
Explanation
The gravitational torque is F × L = (G M m / d^2) L, which balances the restoring torque tau_0 * theta at equilibrium.