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Chemistry · PYQ NEET UG 2025

हिन्दी

Consider the following compounds : \( \mathrm{KO}_2, \mathrm{H}_2\mathrm{O}_2 \) and \( \mathrm{H}_2\mathrm{SO}_4 \). The oxidation states of the underlined elements in them are, respectively,

  1. +1, -1, and +6
  2. +2, -2, and +6
  3. +1, -2, and +4
  4. +4, -4, and +6

Correct answer · Option 1

+1, -1, and +6

Explanation

In \( \mathrm{KO}_2 \), \( \mathrm{K} \) has \( +1 \) and \( \mathrm{O}_2 \) is superioxide ion with \( -1/2 \) oxidation state per \( \mathrm{O} \). In \( \mathrm{H}_2\mathrm{O}_2 \), \( \mathrm{O} \) has \( -1 \) (peroxide). In \( \mathrm{H}_2\mathrm{SO}_4 \), \( \mathrm{S} \) has \( +6 \).
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